What is the sum of the interior angles of the polygon shown below?

Answer:
1440º
Step-by-step explanation:
The sum of the interior angles of a regular polygon of 10 sides = 10*[180 - (360/10)] = 10(180–36) = 10*144 = 1440º
Sorry if some people don't understand, I tried my best to show how I did it.
Step-by-step explanation:
This is a regular decagon, therefore it is classified as a convex polygon.
The formula for the sum of the interior angles of a polygon of this classification is as follows: I=180 degrees (n - 2), where I=measure of the interior angles and n=number of sides.
Solve.
n=10 (decagon)
I=180 (10 - 2)
I=180 (8)
I=1440