Answer:
52
Step-by-step explanation:
Given the the equation h(t) =-[tex]15t^2+ 30t+7[/tex] where t is the time in second
So to find the ball's maximum height we can apply the vertex formula:
t= [tex]\frac{-b}{2a}[/tex]
to find the "x" value of the vertex, then plug that value into the original equation as a substitute for "x".
Standard quadratic form is: [tex]ax^2+bx+c[/tex]
=> a=15, b=30 in our given equation
<=> t = [tex]\frac{-30}{2*-15} =1[/tex]
When t =-1 we have h(t) = [tex]15*1^2+ 30*1+7[/tex] = 52
So the ball's maximum height is: 52
Hope it will find you well.
