Answer: (⁻ ²⁹/₃ , ⁻ ²²/₃ )
Step-by-step explanation:
let x - 2y = 5 be [a] & -3x + 3y = 7 be [b]
First, lets make x the subject of [a] and then substitute [a*] into [b] and solve for y
x - 2y = 5 [a]
x = 5 + 2y [a*]
-------------------------------------
-3 (5 + 2y) + 3y = 7
- 15 - 6y + 3y = 7
-3y = 22
y = - ²²/₃
Now, since y = - ²²/₃, we can substitute for y in [a*]
⇒ x = 5 + 2(- ²²/₃)
x = 5 + ⁻⁴⁴/₃
x = ⁻ ²⁹/₃
∴ the solution for the system of equations is x = ⁻ ²⁹/₃ , y = - ²²/₃ OR (⁻ ²⁹/₃ , ⁻ ²²/₃ )
