An electron moves with velocity v⃗ =(5.8i−6.7j)×104m/s in a magnetic field B⃗ =(−0.81i+0.60j)T.

Determine the x-component of the force on the electron.

Determine the y-component of the force on the electron.

Determine the z-component of the force on the electron.

Respuesta :

Answer:

Fₓ = 0,  [tex]F_{y}[/tex] = 0  and  [tex]F_{z}[/tex] = - 3.115 10⁻¹⁵   N

Explanation:

The magnetic force given by the expression

       F = q v xB

the bold are vectors,  the easiest analytical way to determine this force in solving the determinant

   [tex]F = q \left[\begin{array}{ccc}i&j&k\\5.8&-6.7&0\\-0.81&0.6&0\end{array}\right] 10^{4}[/tex]

   F = 1.6 10⁻¹⁵ [ i( 0-0) + j (0-0) + k^( 5.8 0.60 - 0.81 67) ]

   F =i^0 + j^0   - k^  3.115 10⁻¹⁵   N

   

Fₓ = 0

[tex]F_{y}[/tex] = 0

[tex]F_{z}[/tex] = - 3.115 10⁻¹⁵   N