A 0.15 kg ball is thrown upward and reaches a height of 7 m. What will its KE
be when it falls back down, just before it hits the ground?
A. 1.1J
B. 1.5 J
C. 10.3 J
D. 15 J

Respuesta :

Answer:

10.3

Explanation:

PE  = KE

mgh = 1/2 mv2.

(.15)(9.81)(7)

Answer:

it was in fact 10.3 ;)

Explanation: