If it takes 16.73 mL of a 0.253 M LiOH solution to neutralize10.00 mL of HBr, what is its concentration?

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26-08-2016
Biology

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If it takes 16.73 mL of a 0.253 M LiOH solution to neutralize10.00 mL of HBr, what is its concentration?

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taskmasters taskmasters · Answer 1 · 2016-08-30T08:09:38+02:00

taskmasters taskmasters

30-08-2016

The neutralization reaction is written as:

LiOH + HBr = LiBr + H2O

0.253 mol LiOH / L solution ( .01673 L solution ) ( 1 mol HBr / 1 mol LiOH ) = 4.233 x 10^-3 mol HBr

Concentration of HBr solution = 4.233 x 10^-3 mol HBr / .01 L solution = 0.423 M HBr solution

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