Answer:
33 π
Step-by-step explanation:
Given,
Area of circle = 36 π
Central angle of sector,θ = 11/6 rad
Area of the sector = ?
we know,
A = π r²
36 π = π r²
r = 6
Area of sector
[tex]A = \frac{1}{2} r^2 \theta [/tex]
[tex]A = \frac{1}{2} \times 6^2 \times (\frac{11}{6}\pi)[/tex]
[tex]A = 33\pi \ sqr. units[/tex]
