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Use the basic probability principle to solve the following problem. Express each probability as a fraction reduced to lowest terms. A​ 12-sided die is rolled. The set of​ equally-likely outcomes is StartSet 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 comma 11 comma 12 EndSet . Find the probability of rolling any number except 10.

Respuesta :

Answer:

[tex]\dfrac{11}{12}[/tex]

Step-by-step explanation:

If a 12-Sided die is rolled. The set of​ equally-likely outcomes is:

{1,2,3,4,5,6,7,8,9,10,11,12}

[tex]\text{The probability of rolling a 10}=\dfrac{1}{12}[/tex]

Therefore, the probability of rolling any number except 10 is:

[tex]\text{The probability of rolling a number except 10}\\=1-\text{The probability of rolling a 10}\\=1-\dfrac{1}{12}\\=\dfrac{11}{12}[/tex]

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