Respuesta :

lwittenbornmain

Answer:

[tex]y^3 - 7y^2 - 16y +64[/tex]

Step-by-step explanation:

start by distributing y and - 4 to the equation to get ...

y^3 - 8y^2 + 16y = -y^2 + 32y - 64

then cross factor the number with the same exponents to get ...

y^3 - 7y^2 - 16y + 64

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