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A 3 kg ball traveling to the left at a velocity of 2.3 m/s collides with another 0.5 kg ball traveling to the left at 0.3 m/s. As a result of the collision, the 3 kg ball moves to the left with a velocity of 1.73 m/s. Using the conservation of momentum calculate the velocity of the 0.5 kg ball after the collision. Show all your work. Use the simulation to verify your answer.

Respuesta :

Explanation:

We have,

Mass of a ball is 3 kg, m = 3 kg

Initial velocity of the ball, u = -2.3 m/s

Mass of another ball, m' = 0.5 kg

Initial velocity of another ball, u' = -0.3 m/s

After the collision,

Final velocity of first ball, v = -1.73 m/s

It is required to find the velocity of the 0.5 kg ball after the collision. In the whole process the momentum remains conserved. Using the conservation of linear momentum as :

[tex]mu+m'u'=mv+m'v'[/tex]

v' is the final speed of second ball

[tex]m'v'=mu+m'u'-mv\\\\v'=\dfrac{mu+m'u'-mv}{m'}\\\\v'=\dfrac{3\times (-2.3)+0.5\times (-0.3)-3\times (-1.73)}{0.5}\\\\v'=-3.72\ m/s[/tex]

So, the velocity of the 0.5 kg ball after the collision is 3.72 m/s in left direction.

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