Respuesta :
Answer:
[tex]50\%[/tex]
Step-by-step explanation:
Previous Iron content per serving=1.2 mg
Current Iron content per serving=1.8 mg
Increase in Iron content per serving=1.8-1.2=0.6 mg
Percentage of Iron Increase
[tex]=\dfrac{\text{Increase in Iron Content}}{\text{Previous Iron Content}} X 100\\=\dfrac{0.6}{1.2}X100 \\=50\%[/tex]