Respuesta :

Answer:

0.27 mol

Explanation:

Given data

  • Pressure (P): 5 atm
  • Temperature (T): 70°C
  • Volume (V): 1.5 L
  • Moles of O₂ (n): ?

Step 1: Convert the temperature to the Kelvin scale

When working with gases, we need to convert all temperatures to the absolute scale, using the following expression.

[tex]K = \° + 273.15\\K = 70 + 273.15 = 343 K[/tex]

Step 2: Calculate the moles of gaseous oxygen

We will apply the ideal gas equation.

[tex]P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{5 atm \times 1.5 L}{\frac{0.0821atm.L}{mol.K} \times 343 K} = 0.27 mol[/tex]