Respuesta :
Answer:
The length of the rectangle = 20
The width of the rectangle = 8
Step-by-step explanation:
Step(l):-
let 'W' be the width of the rectangle
Given the length of a rectangle is 4 more than 2 times its width
length of a rectangle(L) = 4+2W
Given the Area of rectangle = 160
Step(ii):-
we know that the area of the triangle = length ×width
(4+2w)w= 160
[tex]2w^{2} +4w-160=0[/tex]
[tex]2(w^{2} +2w- 80)=0[/tex]
[tex]w^{2} +10w-8w- 80=0[/tex]
[tex]w(w +10)-8(w+10)=0[/tex]
[tex](w+10)(w-8) =0[/tex]
[tex]w+10=0 , w-8=0[/tex]
w = -10 and w =8
Step(lll)
we can choose the width is 'w' = 8
now the length of the rectangle = 4+2(8) = 20
The width of the rectangle is '8'
Conclusion:-
The length of the rectangle = 20
The width of the rectangle = 8
