contestada

75.0 g of sodium completely reacts with iron III Carbonate. How many grams of sodium carbonate are formed?

Respuesta :

it would only be 4.5 grams
drpelezo

Answer:

mass = 172.78 grams Na₂CO₃(s) formed

Explanation:

6Na°(s) + Fe₂(CO₃)₃ => 3Na₂CO₃(s) + 2Fe°(s)

moles Na°(s) = 15g/23g/mol = 3.26 mole Na°(s)

From stoichiometry of reaction equation, 3.26 mole Na°(s) => 3/6(3.26) mole Na₂CO₃(s) = 1.63 mole Na₂CO₃(s) x 106 g/mole = 172.78 grams Na₂CO₃(s)

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