Consider this system of equations. Which shows the second equation written in slope-intercept form? y = 3 x minus 2. 10 (x + three-fifths) = 2 y y = 5 x + StartFraction 3 Over 10 EndFraction y = 5 x + 3 y = one-fifth x + StartFraction 3 Over 25 EndFraction y = one-half x + 6

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Question

Consider this system of equations. Which shows the second equation written in slope-intercept form?

[tex]y = 3x - 2.[/tex]

[tex]10(x + \frac{3}{5} ) = 2y[/tex]

A. [tex]y = 5x + \frac{3}{10}[/tex]

B. [tex]y = 5x + 3[/tex]

C. [tex]y = \frac{1}{5} x + \frac{3}{25}[/tex]

D. [tex]y = \frac{1}{2} x + 6[/tex]

Answer:

B. [tex]y = 5x + 3[/tex]

Step-by-step explanation:

Given

Equation 1: [tex]y = 3x - 2.[/tex]

Equation 2: [tex]10(x + \frac{3}{5} ) = 2y[/tex]

Required:

Equivalent of equation 2

To get an equivalent of equation 2 (in slope intercept form), first we have to simplify equation 2

[tex]10(x + \frac{3}{5} ) = 2y[/tex]

Open the bracket

[tex]10*x + 10 *\frac{3}{5} = 2y[/tex]

[tex]10x + \frac{30}{5} = 2y[/tex]

Simplify fraction

[tex]10x + 6 = 2y[/tex]

Divide through by 2

[tex]\frac{10x}{2} + \frac{6}{2} = \frac{2y}{2}[/tex]

[tex]5x + 3 = y[/tex]

Re-arrange

[tex]y = 5x + 3[/tex]

The next step is to compare each of option A through D with [tex]y = 5x + 3[/tex]

A.

[tex]y = 5x + \frac{3}{10}[/tex] is not equal to [tex]y = 5x + 3[/tex]

We check the next available option

B.

[tex]y = 5x + 3[/tex] is equal to [tex]y = 5x + 3[/tex]

This option is equivalent to the second equation in slope-intercept form.

We check further if there are more equivalent options

C.

[tex]y = \frac{1}{5} x + \frac{3}{25}[/tex]

Convert fraction to decimal

[tex]y = 0.2x + 0.12[/tex]

This is not equal to [tex]y = 5x + 3[/tex]

D.

[tex]y = \frac{1}{2} x + 6[/tex]

Convert fraction to decimal

[tex]y = 0.5x + 6[/tex]

This is not equal to [tex]y = 5x + 3[/tex]

Hence, the only equation that is equivalent to the second equation written in slope intercept form is Option B

Answer:

The answer is B

Step-by-step explanation:

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