Answer:
A) 41
Step-by-step explanation:
Let the hypotenuse be denoted by h
perpendicular as p and base as b
According to the Pythagoras theorem
h²=p²+b²
[tex]h = \sqrt{ {p}^{2} + {b}^{2} } [/tex]
[tex]h = \sqrt{ {(40)}^{2} + {(9)}^{2} } [/tex]
[tex]h = \sqrt{1600 + 81} = \sqrt{1681} [/tex]
[tex]h = 41[/tex]
