Respuesta :
Answer:
333 cubic inches
Step-by-step explanation:
Hello, I can help you with this.
according to the question the maximum diameter of a bowling ball is 8.6 inches.
[tex]D_{max}=8.6 inches\\[/tex]
Step one
using this equation find the radius of the ball
remember
Diameter=2*radius
diameter/2= radius
put the value into the equation
8.6 inches/2= radius
radius=4.3 inches
Step two
using the known radius , find the volume
the volume of a sphere is given by
[tex]V=\frac{4}{3}\pi *radius^{3}[/tex]
put the value of radius into the equation
[tex]V=\frac{4}{3}\pi *(4.3\ in) ^{3} \\\\V=\frac{4}{3}\pi *79.507\ in ^{3}\\V=333.03 in ^{3}[/tex]
so, the volume to the nearest tenth of a bowling ball with this diameter is 333 cubic inches.
I hope it helps, have a good day.
Answer:
The volume of the bowling ball to the nearest tenth is v ≈ 106.0π in³ in terms of π or v≈332.9 in³
Step-by-step explanation:
To find the volume of the bowling ball, we will follow the steps below;
First write down the formula for calculating the volume of a sphere
v=[tex]\frac{4}{3}[/tex]πr³
where v = volume of the ball and r = radius of the ball
From the equation given, the diameter of the ball is 8.6 inches but radius is half of diameter, this implies that r= d/2 = 8.6/2 = 4.3, that is; radius=4.3 inches.
Let substitutes the value into the equation
v=[tex]\frac{4}{3}[/tex]×π×(4.3)³
v = [tex]\frac{4}{3}[/tex]×π×79.507
v =106.009π
v ≈ 106.0π in³
we can take π=3.14
v = 106.009×3.14
v =332.86826
v≈332.9 in³
The volume of the bowling ball to the nearest tenth is v ≈ 106.0π in³ in terms of π or v≈332.9 in³
