Answer:
Concentration of the resulting solution = 2.04 M
Explanation:
Data:
M1 = 5.10 M
V1 = 200.0 mL
V2 = 500.0 mL
M2 = ?
By modifying the volume of solution, keeping the amount of solute constant, the concentration changes. To perform the calculations, the equation will be:
[tex]M1*V1=M2*V2[/tex]
Where M1 is the initial concentration of the solution, M2 the final concentration and V is the value of the volumes of the initial and final solution.
Clearing the value of M2 from the equation and replacing the values we have:
[tex]M2=\frac{M1*V1}{V2} =\frac{5.10M*200mL}{500mL} =2.04M[/tex]
Answer:
2.04M
Explanation:
Using C1V1 = C2V2
where;
C1 = Concentration of stock solution = 5.10M
C2 = Final concentration of new solution = x
V1 = Volume of stock solution = 200ml
V2 = Final volume of new solution = 500ml
Inserting the values into the formulae, we have;
5.10 * 200 = x * 500
x = (5.10 * 200) / 500
x = 2.04M
