Answer:
[tex]a_{n}[/tex] = 6n - 5
Step-by-step explanation:
There is a common difference d between the consecutive terms, that is
d =7 - 1 = 13 - 7 = 19 - 13 = 25 - 19 = 6
This indicates the sequence is arithmetic with n th term
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 1 and d = 6, thus
[tex]a_{n}[/tex] = 1 + 6(n - 1) = 1 + 6n - 6 = 6n - 5
Answer:
Step-by-step explanation:
t1 = 1 = 6 * 1 - 5
t2 =7 = 6 * 2 - 5
t3 = 13 = 6 * 3 - 5
t4 = 19 = 6*4 - 5
t5 = 25 = 6*5 - 5
-------------------------
Tn = 6n - 5
Hope it helped :)
