Answer:
The expected number of cheese pizza among the 189 pizzas sold is 42.
Step-by-step explanation:
The distribution of different choices of pizza at the local pizza shop is:
Pizza Frequency
Pepperoni 11
Supreme 7
Cheese 6
Hawaiian 3
_______________
TOTAL 27
Compute the probability of selecting a cheese pizza as follows:
[tex]P(Cheese)=\frac{n(Cheese)}{N}=\frac{6}{27}=0.222[/tex]
Let X = number of cheese pizza sold.
A total of n = 189 pizzas were sold. The probability of selling a cheese pizza is, p = 0.222.
The event of a randomly selected pizza can either cheese or not, is independent of the other pizzas.
The random variable X follows a Binomial distribution with parameters n = 189 and p = 0.222.
The expected value of X is:
[tex]E(X)=np[/tex]
Compute the expected number of cheese pizza among the 189 pizzas sold as follows:
[tex]E(X)=np[/tex]
[tex]=189\times 0.222\\=41.958\\\approx 42[/tex]
Thus, the expected number of cheese pizza among the 189 pizzas sold is 42.
Answer: here is a simple answer
Step-by-step explanation:
6/27 for cheese pizza. Multiply 27 by 7 and 6 by seven. 6x7= 42 27x7= 189. You get 42 to 189.
