Read the question carefully

2 points

1. A basketball court is in the shape of a rectangle

that is 94 feet long and 50 feet wide. What is

the length of a diagonal of the court? Round to

the nearest tenth.

Respuesta :

Answer:

106.5 feet

Step-by-step explanation:

We are given that

Length of rectangle=l=94 feet

Breadth of rectangle,b=50 feet

We have to find the length of diagonal of the court.

Pythagoras theorem:

[tex](Hypotenuse)^2=(perpendicular\;side)^2+(base)^2[/tex]

Using the theorem

[tex](Diagonal)^2=(94)^2+(50)^2[/tex]

[tex](Diagonal)^2=8836+2500[/tex]

[tex](Diagonal)^2=11336[/tex]

[tex]Diagonal=\sqrt{11336}[/tex]

Length of diagonal of court=106.5 feet

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