Answer:
[tex](x-1)^2+(y+1)^2=0.25[/tex]
Step-by-step explanation:
From the given graph it is clear that the center of the circle is (1,-1) and the circle passing through the point (0.5,-1).
So, radius of the circle is
[tex]r=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]r=\sqrt{(0.5-1)^2+(-1-(-1))^2}[/tex]
[tex]r=\sqrt{(-0.5)^2}[/tex]
[tex]r=\sqrt{(0.5)^2}[/tex]
[tex]r=0.5[/tex]
The radius of the circle is 0.5 units.
The standard form of a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex]
where, (h,k) is center and r is radius.
The center of given circle is (1,-1) and radius is 0.5. So, the equation of circle is
[tex](x-(1))^2+(y-(-1))^2=(0.5)^2[/tex]
[tex](x-1)^2+(y+1)^2=0.25[/tex]
Therefore, the required equation is [tex](x-1)^2+(y+1)^2=0.25[/tex].
