Answer:
112.76°
Explanation:
The angle of the reflected light is the same as the angle of the incident light:
[tex]\theta_r=\theta_i=39.0\°[/tex]
The refracted angle is obtained by using the Snell's law:
[tex]n_1sen\theta_1=n_2sin\theta_2[/tex]
n1: air index of refraction ≈ 1.00
n2: ice index of refraction = 1.31
By replacing the values for the incident angle and the index of refraction you can calculate the angle of refraction:
[tex](1.00)sin(39.0\°)=(1.33)sin\theta_2\\\\\theta_2=sin^{-1}(\frac{(1.00)sin(39.0\°)}{1.33})=28.24\°[/tex]
the angle between the reflected and refracted angle will be:
[tex]\phi=(90\°-39.0\°)+(90\°-28.24\°)=112.76\°[/tex]
where you have taken into account that the angles aremeasured according to the horizontal axis.
