Answer:
10 combinations
Step-by-step explanation:
What we have to do is calculate the number of combinations of 3 in 5.
The formula for the combinations is:
nCr = n!/r!(n-r)!
in this case n = 5 and r = 3
replacing
5C3 = 5!/3!(5-3)! = 5!/(3!*2!)
5C3 = 10
So there are 10 combinations in which Erika can enjoy the books on her trip
Answer:
The number of different combinations of 3 books that Erika can take on a trip if she has 5 books is 10
Step-by-step explanation:
Here we have the formula for combination given as follows;
[tex]\binom{n}{r} = \frac{n!}{r!(n-r)!}[/tex]
Where n is the number of set elements = 5 and
r = Number of subset elements = 3
Therefore, plugging the values, we have;
[tex]\binom{5}{3} = \frac{5!}{3!(5-3)!} = \frac{120}{6(2)} = 10[/tex]
Therefore, the number of different combinations of 3 books that Erika can take on a trip if she has 5 books = 10.
