Respuesta :
Answer:
x^2 + (y – 3)^2 = 36
Step-by-step explanation:
The standard equation of a circle with center at (h, k) and radius r is
(x - h)^2 + (y - k)^2 = r^2.
If the center lies on the y-axis, then h = 0: (x - 0)^2 + (y - k)^2 = r^2
If the circle diameter is 12, then the circle radius is 6, and so r^2 = 36
So, among the given equations, your
x^2 + (y – 3)^2 = 36 is correct (but only if you use " ^ " for exponentiation).
The equation that represents circles that have a diameter of 12 units and a center that lies on the y-axis is x²+ (y-3)² = 36
The standard form for finding the equation of a circle is expressed as;
(x-a)^2 + (y-b)^2 = b=r^2
where;
(a, b) is the center of the circle
r is the radius of the circle
Given the following
diameter = 12 units
radius = 12/2 = 6 units
If the centre lies on the y-axis, the center will be at (0, 3)
Substituting into the formula, we will have (x-0)^2 + (y-3)^2 = 6^2 equivalent to x²+ (y-3)² = 36
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