contestada

At high temperatures, carbon reacts with O2 to produce CO as follows: C(s) O2(g) 2CO(g). When 0.350 mol of O2 and excess carbon were placed in a 5.00-L container and heated, the equilibrium concentration of CO was found to be 0.060 M. What is the equilibrium constant, Kc, for this reaction

Respuesta :

Answer:

Value of [tex]K_{c}[/tex] is 0.090.

Explanation:

Initial molarity of [tex]O_{2}[/tex] = [tex]\frac{0.350}{5.00}M[/tex] = 0.0700 M

Construct an ICE table corresponding to the combustion reaction of carbon to determine [tex]K_{c}[/tex]

                       [tex]C(s)+O_{2}(g)\rightarrow 2CO(g)[/tex]

              I (M):    -      0.0700        0

             C (M):  -          -x             +2x

             E (M):   -    0.0700-x       2x

So, [tex]K_{c}=\frac{[CO]^{2}}{[O_{2}]}[/tex]  , where [CO] and [tex][O_{2}][/tex] represents equilibrium concentration of CO and [tex]O_{2}[/tex] respectively.

Here, [tex][CO]=2x=0.060[/tex]

       ⇒x = 0.030

So, [tex][O_{2}][/tex] = 0.0700-x = (0.0700-0.030) = 0.040

Hence,  [tex]K_{c}=\frac{(0.060)^{2}}{0.040}=0.090[/tex]

Otras preguntas