Answer:
(a)
The function f is continuous at [1,e] and differentiable at (1,e), therefore
the mean value theorem applies to the function.
(b)
[tex]c = e-1 \\[/tex] = 1.71828
Step-by-step explanation:
(a)
The function f is continuous at [1,e] and differentiable at (1,e), therefore
the mean value theorem applies to the function.
(b)
You are looking for a point [tex]c[/tex] such that
[tex]\frac{1}{c} = \frac{\ln(15e)-\ln(15*1)}{e-1} = \frac{\ln(15e/15)}{e-1} = \frac{\ln(e)}{e-1} = \frac{1}{e-1}[/tex]
You have to solve for [tex]c[/tex] and get that
[tex]c = e-1 \\[/tex] = 1.71828