Answer:
The maximum discharge rate of water is 4.6 L/s
Explanation:
Given data:
d=diameter=8 m
h=height=3 m
The mathematical expression for the theoritical velocity is:
[tex]v_{th} =\sqrt{2gh} =\sqrt{2*9.8*3} =7.6681m/s[/tex]
The maximum discharge can be calculate by:
[tex]Q=C_{d} Av_{th}[/tex]
Here
Cd=coefficient of discharge=0.855
[tex]Q=0.855*\frac{\pi }{4} *d^{2} *vx_{th} =0.855*\frac{\pi }{4} *0.03^{2} *7.6681=0.0046m^{3} /s=4.6L/s[/tex]
