Answer:
0.084 M
Explanation:
molar mass of Na3PO4 = 3*23 + 31 + 4*16 = 164 g/mol
moles of Na3PO4 = mass / molar mass = 0.46/164 = 0.0028 mol
There are 3 moles of Na+ in 1 mol of Na3PO4, so there are 3*0.0028 = 0.0084 moles of Na+ in the solution
Molarity is defined as:
M = moles of solute/litre of solution
100 ml are equivalent to 0.1 L
Therefore:
M of Na+ = 0.0084/0.1 = 0.084 M
