Answer:
Solubility= 1.08×10-12
Explanation:
Take the cube root of 1.27×10-36
Answer:
The solubility of CuX is 1.425x10⁻⁷M
Explanation:
Given:
initial concentration of NaCN=0.2M
Ksp=1.27x10⁻³⁶
The reaction are:
CuX → Cu²⁺ + X²⁺, Ksp=1.27x10⁻³⁶
Cu²⁺ + 4CN⁻ → (Cu(CN)₄)²⁻, Kf=1x10²⁵
The overall reaction is:
CuX + 4CN⁻ → (Cu(CN)₄)²⁻ + X²⁺
The equilibrium constant is:
K=Ksp*Kf=1.27x10⁻³⁶*1x10²⁵=1.27x10⁻¹¹
CuX + 4CN⁻ → (Cu(CN)₄)²⁻ + X²⁺
I - 0.2 0 0
C - -4 +x +x
E - 0.2-4 x x
The equation for equilibrium is:
[tex]K=\frac{[Cu(CN)4]^{2} [X]}{[CN]^{4} } \\1.27x10^{-11} =\frac{x^{2} }{(0.2-x)^{4} }[/tex]
Here, solving for x:
x=1.425x10⁻⁷M=CuX
