Answer:
By graphing the line, we have the equation y = [tex]\frac{3}{4} x -4.5[/tex]
Step-by-step explanation:
What this question is asking us is to find the equation of the line with the value of the slope given in the question and also passing through the point in the question
For a straight line, the general equation can be represented as
y = mx + c
where m is the slope of the line and c is the y intercept. From the question, we have the value of the slope, what we have left to find is the value of the intercept. We find this by inserting the x, y and the slope value into the general equation of a straight line.
We have;
-3 = 3/4(2) + c
c = -3 - 6/4
c = -3-1.5 = -4.5
Thus, the equation of the line is;
y = [tex]\frac{3}{4} x -4.5[/tex]
The graph of the given line is required.
The required graph is attached below.
The slope of the line is [tex]m=\dfrac{3}{4}[/tex]
The point is [tex](2,-3)[/tex]
The equation is
[tex]y-(-3)=\dfrac{3}{4}(x-2)\\\Rightarrow y+3=\dfrac{3}{4}x-\dfrac{3}{2}\\\Rightarrow y=\dfrac{3}{4}x-\dfrac{9}{2}[/tex]
Finding another point
[tex]x=0[/tex]
[tex]y=0-\dfrac{9}{2}[/tex]
[tex](0,-\dfrac{9}{2})[/tex]
Join the two points and the graph is drawn.
Learn more:
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