The circumference of the inner circle is 22 ft. The distance between the inner circle
and the outer circle is 3 ft. By how many feet is the circumference of outer circle
22
greater than the circumference of the inner circle? Use 7 for it.
ft greater than the circumference of the inner circle.
The circumference of outer circle is about
(Round to the nearest tenth as needed.)
hol hornemar​

Respuesta :

Answer:

Radius of outer circle = 6.5 ft

Circumference outer circle = 40.9 ft

Step-by-step explanation:

We can find the radius of the inner circle

C = 2 * pi r

22 = 2 * pi *r

22 /2pi = 2pi r/2pi

11/pi = r

11/(22/7) =r

3.5 =r

Add 3 to get the radius of the outer circle

The radius of the outer circle is 3+3.5 = 6.5 ft

We can find the circumference of the outer circle by

C = 2*pi*r

C = 2 * 22/7 *6.5

C=40.85714286

Rounding to the nearest tenth

C = 40.9 ft

Answer:

18.9 ft

40.9 ft

Step-by-step explanation:

Circumference of the inner circle:

22 = 2 pi × r

22 = 2 × 22/7 × r

r = 7/2 = 3.5

Distance between the circles is the difference between the radii

Outer circle radius: 3.5 + 3 = 6.5

Circumference of the outer circle is:

2 × 22/7 × 6.5

40.85614286

To the nearest tenth: 40.9

Difference between the circumferences:

40.9 - 22

18.9 ft