Answer : The mass of [tex]NaCl[/tex] needed are, 44.5 grams.
Explanation :
First we have to calculate the moles of Na.
[tex]\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}=\frac{17.5g}{23g/mol}=0.761mol[/tex]
Now we have to calculate the moles of NaCl.
The balanced chemical reaction is:
[tex]2NaCl\rightarrow 2Na+Cl_2[/tex]
From the reaction, we conclude that
As, 2 mole of [tex]Na[/tex] produces from 2 mole of [tex]NaCl[/tex]
So, 0.761 mole of [tex]Na[/tex] produces from 0.761 mole of [tex]NaCl[/tex]
Now we have to calculate the mass of [tex]NaCl[/tex]
[tex]\text{ Mass of }NaCl=\text{ Moles of }NaCl\times \text{ Molar mass of }NaCl[/tex]
Molar mass of [tex]NaCl[/tex] = 58.5 g/mole
[tex]\text{ Mass of }NaCl=(0.761moles)\times (58.5g/mole)=44.5g[/tex]
Therefore, the mass of [tex]NaCl[/tex] needed are, 44.5 grams.
