Answer:
B.) M + 7
Explanation:
Since the average (arithmetic mean) of two numbers is equal to the sum of the two numbers divided by 2, the equations X = m+9/ 2 , Y = 2m+15/2 , Z = 3m+18 /2 are true. The average of x, y, and z is given by x+y+z /3 . Substituting the expressions in m for each variable (x, y, z) gives:
[ m+9 /2 + 2m+15/ 2 + 3m+18/2 ] / 3
This fraction can be simplified to m+7.
Answer:
B
Explanation:
Let's convert these written languages into mathematical expressions:
"x is the average of m and 9": x = [tex]\frac{m +9}{2}[/tex]
"y is the average of 2m and 15": y = [tex]\frac{2m +15}{2}[/tex]
"z is the average of 3m and 18": z = [tex]\frac{3m +18}{2}[/tex]
Now, we want to find the value of the average of x, y, and z in terms of m. The average of x, y, and z can be written as: [tex]\frac{x+y+z}{3}[/tex]. Let's substitute each of the expressions we have above in for x, y, and z:
[tex]\frac{\frac{m +9}{2}+\frac{2m +15}{2}+\frac{3m +18}{2}}{3}=\frac{(m+9)+(2m+15)+(3m+18)}{6} =\frac{6m+42}{6} =m+7[/tex]
The answer is B.
Hope this helps!
