Answer :
(a) The molecular equation will be,
[tex]CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)[/tex]
(b) The complete ionic equation in separated aqueous solution will be,
[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)+2H^{+}(aq)+2Cl^{-}(aq)\rightarrow Ca^{2+}(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)[/tex]
(c) The net ionic equation will be,
[tex]CO_3^{2-}(aq)+2H^{+}(aq)\rightarrow H_2O(l)+CO_2(g)[/tex]
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
(a) The molecular equation will be,
[tex]CaCO_3(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+H_2O(l)+CO_2(g)[/tex]
(b) The complete ionic equation in separated aqueous solution will be,
[tex]Ca^{2+}(aq)+CO_3^{2-}(aq)+2H^{+}(aq)+2Cl^{-}(aq)\rightarrow Ca^{2+}(aq)+2Cl^-(aq)+H_2O(l)+CO_2(g)[/tex]
In this equation, [tex]Ca^{2+}\text{ and }Cl^-[/tex] are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
(c) The net ionic equation will be,
[tex]CO_3^{2-}(aq)+2H^{+}(aq)\rightarrow H_2O(l)+CO_2(g)[/tex]
