Answer:
3 and 28
Step-by-step explanation:
note ([tex]\frac{f}{g}[/tex] )(x ) = [tex]\frac{f(x)}{g(x)}[/tex]
[tex]\frac{f(x)}{g(x)}[/tex]
= [tex]\frac{x^2+2x-3}{x^2-9}[/tex] and
([tex]\frac{f}{g}[/tex] )(4) = [tex]\frac{4^2+2(4)-3}{4^2-9}[/tex] = [tex]\frac{16+8-3}{16-9}[/tex] = [tex]\frac{21}{7}[/tex] = 3
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(f + g)(x) = f(x) + g(x)
f(x) + g(x)
= x² + 2x - 3 + x² - 9 = 2x² + 2x - 12 and
(f + g)(4) = 2(4)² + 2(4) - 12 = 2(16) + 8 - 12 = 32 + 8 - 12 = 28
