Answer:
a.2010 rad/min
b.2412 feet/min
Step-by-step explanation:
We are given that
Diameter of wheel,d=2.4 feet
Radius,r=[tex]\frac{d}{2}=\frac{2.4}{2}=1.2feet[/tex]
a.Rate=320 rev/minute
1 rev=[tex]2\pi[/tex] radian
320 rev/minute=[tex]320\times 2\pi=640\pi radian/minute[/tex]
Where [tex]\pi=3.14[/tex]
Angular speed=[tex]640\times 3.14=2010 rad/min[/tex]
b.Speed,v=[tex]r\omega[/tex]
[tex]v=2010\times 1.2=2412 feet/min[/tex]
