One mole of an ideal gas was found to occupy a volume of 20.0 L a pressure of 930 MMHG and a temperature of 25°C what is the value of the gas constant in L times MMHG divided by Mol times K

Respuesta :

Answer : The value of the gas constant is, [tex]62.4\text{ mmHg.L/mol.K}[/tex]

Explanation :

Using ideal gas equation:

PV = nRT

where,

P = pressure of gas = 930 mmHg

V = volume of gas = 20.0 L

n = number of moles of gas = 1 mol

T = temperature of gas = [tex]25^oC=273+25=298K[/tex]

R = gas constant = ?

Now put all the given value in the above formula, we get:

[tex]930mmHg\times 20.0L=1mol\times R\times 298K[/tex]

[tex]R=62.4\text{ mmHg.L/mol.K}[/tex]

Therefore, the value of the gas constant is, [tex]62.4\text{ mmHg.L/mol.K}[/tex]

Answer:

62.4

Explanation:

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