Answer:
The fraction of the maximum intensity a distance y 5 0.600 cm away from the central maximum is 0.97.
Explanation:
d = 0.180 mm = 1.8 x 10⁻⁴ m
L = 80 cm = 0.8 m
λ = 656.3 nm = 6.563 x 10⁻⁷ m
y = 0.6 cm = 6 x 10⁻³ m
we know that the equation of the intensity for two slits interference equation is
I = [tex]I_{max}[/tex] cos²(πdy/λL)
where
I = intensity
[tex]I_{max}[/tex] = maximum intensity
d = distance of two slits
y = the distance of the interference with the central
L = the distance of screen and the slits
λ = wavelength
so,
I = [tex]I_{max}[/tex] cos²(πdy/λL)
I/[tex]I_{max}[/tex] = cos²(πdy/λL)
= cos²[π (1.8 x 10⁻⁴) (6 x 10⁻³)/(6.563 x 10⁻⁷) (0.8 )]
= 0.97
