Answer:
The force exerted between s and q is four times that force between S and p
Explanation:
Given that ;
A source charge S
Is at a 1 unit distance from another charger q
The force between S and q is given by columbs law;
F=k*q*S/r^2
F= K*q*S/1
F= KqS ( this is the force between charges q and S)
Also charge between S and P at 2 units distance is
F=K*P*S/r^2
F= K*P*S/2^2
F=KpS/4
Hence 4F=KpS (This is the force between p and S)
It can be seen that 4F=4kqs=kpS
