Answer:
Explanation:
Wavelength of light λ = 610 nm
Screen distance D = 3.00 m
Slit separation be d
position of first bright fringe = λ D / d
Putting the values given
4.84 x 10⁻³ = [tex]\frac{610\times10^{-9}\times3}{d}[/tex]
d = [tex]\frac{610\times10^{-9}\times3}{4.84\times10^{-3}}[/tex]
= 378.1 x 10⁻⁶ m
Let the required wave length be λ₁
Equation for position of dark fringe is given by following relation
x = [tex]\frac{(2n+1)\lambda\times D}{2d}[/tex]
Putting the value in the equation
4.84 x 10⁻³ = [tex]\frac{\lambda_1\times 3 }{2\times378.1\times10^{-6}}[/tex] , for first dark fringe n = 0
λ₁ = 1220 x 10⁻⁹
= 1220 nm .
