Respuesta :
Answer: The number of moles of excess reagent remain unreacted will be, 6.004 moles.
Explanation : Given,
Moles of [tex]C_4H_{10}[/tex] = 1.332 mol
Mass of [tex]O_2[/tex] = 6.504 mol
First we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
[tex]C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2[/tex]
From the balanced reaction we conclude that
As, 13 mole of [tex]O_2[/tex] react with 1 mole of [tex]C_4H_{10}[/tex]
So, 6.504 moles of [tex]O_2[/tex] react with [tex]\frac{6.504}{13}=0.5003[/tex] moles of [tex]C_4H_{10}[/tex]
From this we conclude that, [tex]C_4H_{10}[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]O_2[/tex] is a limiting reagent and it limits the formation of product.
Number of moles remain unreacted = 6.504 mol - 0.5003 mol = 6.004 mol
Therefore, the number of moles of excess reagent remain unreacted will be, 6.004 moles.
