Answer:
(a)0
(b)1
(c)2
Step-by-step explanation:
The function g is defined as follows:
[tex]g=\left\{\begin{array}{ccc}-\frac{1}{4}x+1, &x<-2 \\-(x+1)^2+1, &-2\leq x\leq2\\2,&x>2\end{array}\right\\[/tex]
[tex](a)g(x)=-(x+1)^2+1, -2\leq -2\leq2\\g(-2)=-(-2+1)^2+1=0\\[/tex]
[tex](b)g(x)=-(x+1)^2+1, -2\leq -1\leq2\\g(-1)=-(-1+1)^2+1=1\\[/tex]
[tex](c)g(x)=2, x>2\\Therefore, g(4)=2[/tex]
