Respuesta :
Answer:
A) The magnitude of current is
2.59 A
B) The direction is clockwise
Explanation:
Please find the attached files for the solution


We have that for the Question , it can be said that the magnitude and direction (clockwise or counterclockwise) of the current in the loop is
i=2.11A clockwise
From the question we are told
A rectangular loop with dimensions 4.20 cm by 9.50 cm carries current III. The current in the loop produces a magnetic field at the center of the loop that has magnitude 5.40×10−5 T and direction away from you as you view the plane of the loop.
What are the magnitude and direction (clockwise or counterclockwise) of the current in the loop?
Generally the equation for the Magnetic Field at loop center is mathematically given as
[tex]B=\frac{4\mui}{2\pi(l/2)}+2\frac{\mu i}{2\pi(b/2)}[/tex]
Therefore
[tex]5.80*10^{-5}T=\frac{4(4 \pi*10^{-7})}{2 \pi}* \frac{1}{9.50*10^{-2}+4.20*10^{-2}}[/tex]
[tex]i=\frac{5.80*10^{-5}}{2.74*10^{-5}}[/tex]
i=2.11A
Therefore
the magnitude and direction (clockwise or counterclockwise) of the current in the loop is
i=2.11A clockwise
For more information on this visit
https://brainly.com/question/23379286