Answer:
fourth option
Step-by-step explanation:
note that ([tex]\frac{f}{g}[/tex] )(x)x) = [tex]\frac{f(x)}{g(x)}[/tex]
[tex]\frac{f(x)}{g(x)}[/tex] = [tex]\frac{2x^2-5x-3}{2x^2+x}[/tex] ← factorise numerator/ denominator
= [tex]\frac{(x-3)(2x+1)}{x(2x+1)}[/tex] ← cancel the common factor (2x + 1)
= [tex]\frac{x-3}{x}[/tex] where x ≠ 0, - [tex]\frac{1}{2}[/tex]
