Respuesta :
Area of a rectangle=lenght x width.
width=x
length=x+3
we can suggest this equation:
x(x+3)=40
x²+3x=40
x²+3x-40=0
we solve this square equation:
x=[-3⁺₋√(9+160)] / 2
x=(-3⁺₋13)/2
we have two solutions:
x₁=(-3-13)/2=-8 this solution isn´t valid.
x₂=(-3+13)/2=5
lenght=x+3=5+3=8
Answer: the lenght, in inches, of the rectangle is 8 .
(2) 8
width=x
length=x+3
we can suggest this equation:
x(x+3)=40
x²+3x=40
x²+3x-40=0
we solve this square equation:
x=[-3⁺₋√(9+160)] / 2
x=(-3⁺₋13)/2
we have two solutions:
x₁=(-3-13)/2=-8 this solution isn´t valid.
x₂=(-3+13)/2=5
lenght=x+3=5+3=8
Answer: the lenght, in inches, of the rectangle is 8 .
(2) 8
Let's say W=the width of the rectangle
if width times length equals the area, then...
W x (3+W)=40
Length = 8
Width = 5
I started by factorising 40:
2, 2, 2, 5.
Then you just find a way to arrange those numbers that works
if width times length equals the area, then...
W x (3+W)=40
Length = 8
Width = 5
I started by factorising 40:
2, 2, 2, 5.
Then you just find a way to arrange those numbers that works