His displacement from his starting point compare with the first trial : C)One-ninth as large.
Further explanation
Regular straight motion is the motion of objects on a straight track that has a fixed speed
Formula used
[tex]\large{\boxed{\bold{S=v\times\:t}}}[/tex]
S = distance = m
v = speed = m / s
t = time = seconds
Straight motion changes regularly are the straight motion of objects that have a fixed acceleration
Formula used
[tex]\large{\boxed{\bold{St=vo.t+\frac{1}{2}at^2}}}[/tex]
V = vo + at
Vt² = vo² + 2as
St = distance on t
vo = initial speed
vt = speed on t
a = acceleration
The skateboarder performs 2 movements without initial speed (vo = 0) so it is considered free fall motion
- 1. motion decreases with time t = 6s
St1 = vot + 1/2 at² ⇒ vo = 0 so,
St1 = 1/2 .at² ⇒ a = g
St1 = 1/2.g (6²)
St1 = 1/2 g.36
St1 = 18 g
- 2. motion decreases with time t = 2s
St2= 1/2.g (2²)
St2 = 1/2 g.4
St2 = 2 g
So his displacement from his starting point compare with the first trial :
[tex]\frac{St_2}{St_1} =\frac{2g}{18g}[/tex]
[tex]\frac{St_2}{St_1}=\frac{1}{9}[/tex]
The correct answer : C)One-ninth as large.
Learn more
The distance of the elevator
brainly.com/question/8729508
resultant velocity
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the average velocity
brainly.com/question/5248528
Keywords: free fall motion
, gravitational acceleration, fixed acceleration
