√3 tan (3 theta) + 1 = 0
√3 tan ( 3 theta) = -1
tan (3 theta ) = -√3/3
3 theta = 5π/6 + kπ /: 3
Answer:
theta = 5π/18 + kπ/3, k ∈ Z
Note: √3 tan (3 theta ) + 1 = 1 is probably a wrong equation, but it can be solved also.
tan ( 3 theta ) = 0
3 theta = kπ /:3
theta = kπ/3, k∈ Z
