Respuesta :
The function is continuous for all real numbers:
f ( x ) = ( x² - 4 ) / ( x + 2 ) = [tex] \frac{(x-2)(x+2)}{x + 2} [/tex] =
= x - 2
f ( -2 ) = - 2 - 2 = - 4
f ( x ) = ( x² - 4 ) / ( x + 2 ) = [tex] \frac{(x-2)(x+2)}{x + 2} [/tex] =
= x - 2
f ( -2 ) = - 2 - 2 = - 4
Answer: -4
Step-by-step explanation:
If f is continuous you know that lim x-> a f(x) = f(a)
Since the limit x-> -2 = (x-2)(x+2)/(x+2) = -4, this is done by canceling out the top term and the bottom term (x+2)
Your answer is -4