Answer:
[tex]\large\boxed{a.\ \left(\dfrac{16}{7},\ \dfrac{19}{7}\right)}[/tex]
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}5x-2y=6&(1)\\x=5-y&(2)\end{array}\right\\\\\text{Put (2) to (1):}\\\\5(5-y)-2y=6\qquad\text{use the distributive property}\\(5)(5)+(5)(-y)-2y=6\\25-5y-2y=6\qquad\text{subtract 25 from both sides}\\-7y=-19\qquad\text{divide both sides by (-7)}\\y=\dfrac{19}{7}\\\\\text{Put it to (2):}\\\\x=5-\dfrac{19}{7}\\\\x=\dfrac{35}{7}-\dfrac{19}{7}\\\\x=\dfrac{16}{7}[/tex]
